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### 2001-B: Numeric Algebra 2

• Topic Cluster: Pure Mathematics
• Topic: Algebra
• Objective: Solve algebraic equations with three or four steps to find a numeric answer.
• Content:
• Level: 2

1. $$4 + 11 = 3x - 6$$
2. $$55 = 12 x^2 - 53$$
3. $$19x = 24x - 15$$
4. $$6 = \frac{24}{x}$$
5. $$19 = \frac{31}{x}$$
6. $$36 = 16 + 2 \cdot 12 \left( x - 12 \right)$$
7. $$100 = 64 + 2 \cdot 10 \left( x - 30 \right)$$
8. $$81 = 25 + 2 \cdot \left( 18 - x \right)$$
9. $$64 = 16 + 2 \cdot \left( 20 - x \right)$$
10. $$100 = \frac{2 \cdot 4 \cdot 6}{x}$$
11. $$24 = 6 \sqrt{\frac{x}{3}}$$
12. $$40 = \frac{1}{4} \sqrt{\frac{x + 10}{3}}$$
13. $$50 = \frac{2}{3} \sqrt{\frac{x + 13}{0.4}}$$
14. $$500 = \frac{1}{2} \cdot 4 \cdot x^2 + 4 \cdot 10 \cdot 12$$
15. $$200 = \frac{1}{2} \cdot x \cdot 5^2 + x \cdot 10 \cdot 14$$
16. $$120 = \frac{3 \cdot 9 \cdot 12}{x^2}$$
17. $$300 = \frac{12 \cdot 3x}{9^2}$$
18. $$400 = \frac{3 \cdot 2 \cdot \left( 10 - 2 \right) }{x^2}$$
19. $$\frac{1}{x} = \frac{1}{2} + \frac{1}{4}$$
20. $$\frac{1}{10} = \frac{1}{x} + \frac{1}{20}$$

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